The school that rob goes to is selling tickets to a spring musical. On the first day of ticket sales the school sold 22 senior citizen tickets and 10 child tickets for a total of $126. The school took in $51 on the second day by selling 3 senior citizen tickets and 9 child tickets. Find the price of a senior citizen ticket and the price of a child ticket.

price of a senior citizen ticket = $3.71

Let the price of a child ticket = $4.43

Step-by-step explanation:

Let the price of a senior citizen ticket = x

Let the price of a child ticket = y

On the first day of ticket sales the school sold 22 senior citizen tickets and 10 child tickets for a total of $126. This will be:

22x + 10y = 126 i

The school took in $51 on the second day by selling 3 senior citizen tickets and 9 child tickets. This will be:

3x + 9y = 51 ii

22x + 10y = 126 i

3x + 9y = 51 ii

Multiply equation i by 3

Multiply equation ii by 22

66x + 30y = 378 iii

66x + 198y = 1122 iv

Subtract iii from iv

168y = 744

y = 744/168

y = 4.43

Since 3x + 9y = 51

3x + 9(4.43) = 51

3x + 39.87 = 51

3x = 51 - 39.87

3x = 11.13

x = 11.13/3

x = 3.71

6, 10

9, -13

12, -21

18, -23

step-by-step explanation:

you just add 6 to the x-coordinate and subtract 10 from the y-coordinate.

answer is : muchas/tipicas

have a nice day!

~recklesschicken