A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the time that the rocket will hit the ground, to the nearest 100th of second. y = -16x + 121x + 83

the answer is a

step-by-step explanation:

because if you put 1 in to the square root of x it equals 300.

this is false ^.^ lol

d

step-by-step explanation:

the two points from this line are   (0,4)   & (2,-2)

we can call

now, lets find the slope (m):

now finding b (the y intercept). this is the point at the y-axis where the line cuts the axis. looking at the graph, it is y = 4. so the point is 4. hence b = 4

the slope-intercept form is given by  

putting the points, we have:

d is the correct answer.