Which values for A and B will create infinitely many solutions for this system of equations? A x minus y = 8. 2 x + y = B.
A = 2, B = 8
A = negative 2, B= 8
A = 2, B= negative 8
A = negative 2, B= negative 8

you can first factor out the n to get n(1+5). we know that 1+5 is 6, so we just have 6n.

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

exactly you go it

step-by-step explanation: