Find the expression that represents the length of the hypotenuse of a right triangle whose legs measure m^2-n^2 and 2mn ​

√m^4 + n^4 +2m²n²

Step-by-step explanation:

Given the following

Opposite= m²-n²

adjacent = 2mn

Using pythagoras theorem

hyp² =  (m²-n²)²+(2mn)²

hyp² = m^4-2m²n²+n^4+4m²n²

hyp² = m^4 + n^4 +2m²n²

hyp = √m^4 + n^4 +2m²n²

hence the required expression is  √m^4 + n^4 +2m²n²

answer: the angel abc is 30°,and the abc is a triangle where the angel bac is 90°

so ac is the half of 24=12ft,and from the pythagorean theorem we find ba

ba=√bc^2-ac^2=√576-144=√432=12√3ft

so bac is 12+12√3=12(1+√3)ft

step-by-step explanation:

infinity is the answer