g A survey of athletes at a high school is conducted, and the following facts are discovered: 41% of the athletes are football players, 52% are basketball players, and 35% of the athletes play both football and basketball. An athlete is chosen at random from the high school: what is the probability that the athlete is either a football player or a basketball player

0.58 = 58% probability that the athlete is either a football player or a basketball player

Step-by-step explanation:

We solve this question treating the probabilities as Venn's sets.

I am going to say that:

Event A: Athlete is a football player.

Event B: Athlete is a basketball player.

41% of the athletes are football players:

This means that

52% are basketball players

This means that

35% of the athletes play both football and basketball.

This means that

What is the probability that the athlete is either a football player or a basketball player

This is , which is given by the following equation:

. So

0.58 = 58% probability that the athlete is either a football player or a basketball player

there would be 162.15 calories in this cereal.

step-by-step explanation:

i would be 2,000 just get the square root of 50 which is 2500 and the divid 4/5 and last thing multiply the answer you get for that by the square root of 50

step-by-step explanation: