3(r-1) -2(r+3) =0 anybody know the answer to that ?

r = 9

Step-by-step explanation:

3(r - 1) - 2(r + 3) = 0

First, use the distributive property.

3r - 3 -2r - 6 = 0

Now, isolate the variable "r" to one side by adding the opposite of the whole numbers to each side so it cancels it out on the left ide and adds it to the right.

3r - 3 -2r - 6 = 0

   +3        +6    +3 +6

3r - 2r = 9

Subtract the r's.

r = 9

Now that we know r = 9, we can plug in 9 into the original (but distributed) expression for every time it uses the variable "r" to check our work.

3r - 3 -2r - 6 = 0

3(9) - 3 - 2(9) - 6 = 0

27 - 3 - 18 - 6 = 0

24 - 24 = 0

0 = 0

So, r = 9 is true.

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