Use the graph of f(x)={x+3,x<−1−4x−2,x≥−1. The graph with X-coordinate marks -4, -2, 0, 2, 4 and Y-coordinate mark -4, -2, 0, 2, 4. There is function f which starts intersects y-axis at (0, -2), and the x-axis at (-0.5, 0), then it increases till (-1, 2) then decreases and intersects x-axis at (-3, 0).

Over what part of the domain is function f decreasing?

A. x < −1
B. x ≥ 2
C. x ≥ −1
D. x < 2

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

answer: x=3 and y=4

step-by-step explanation: