In a shop, the cost of 4 shirts, 4 pairs of trousers and 2 hats are $560. The cost of 9 shirts, 9 pairs of trousers and 6 hats is $1,290. What is the total cost of 1 shirt, 1 pair of trousers and 1 hat?

thx for the points (impossible question)

Step-by-step explanation:

i'm a b0omer give other answer brainliest

Given:

4 shirts, 4 pairs of trousers , and 2 hats is $560

9 shirts, 9 pairs of trousers , and 6 hats is $1,290

1) Let x be the price of 1 shirt

Let y be the price of 1 pair of trousers

Let z be the price of 1 hat

2) 4x + 4y + 2z = 560

3) 9x + 9y + 6z = 1,290

4) (9x + 9y + 6z) / 3 = 1,290 / 3

3x + 3y + 2z = 430

5)

4x + 4y + 2z = 560

- (3x + 3y + 2z = 430)

x + y = 130

6) 3(x+y) + 2z = 430

3(130) + 2z = 430

390 + 2z = 430

2z = 430 - 390

2z = 40

z = 40/2

z = 20

7) x = price of 1 shirt; y = price of 1 pair of trousers ; z = price of 1hat

x + y = 130 ; z = 20

130 + 20 = 150

The price of 1 shirt, 1 pair of trousers, and 1 hat is $150.

So this is not impossible!

-chiyoku toga

example answer: "to determine if a sum is reasonable you can round each number to the nearest whole and compare the estimated sum to the actual sum."

hope this you and anyone else who needs the answer : ^)