Line AB and line BC form a right angle at point B. If A = (-3, -1) and B + (4, 4), what is the equation of line BC? A.) x + 3y = 16
B.) 2x + y = 12
C.) -7x - 5y = -48
D.) 7x - 5y = 48

C.) -7x - 5y = -48

Step-by-step explanation:

slope AB = (y2 - y1)/(x2-x1)

= {4-(-1)}/{4-(-3)} = 4+1/4+3 = 5/7

slope of BC = -1 ÷ 5/7 = -1 × 7/5 = -7/5

taking -7x - 5y = -48

-5y = 7x -48

y = 7x/-5 - 48

y = -7/5x -48

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step-by-step explanation:

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check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.