A22 gram sample of a substance that's used to preserve fruit and vegetables has a k-value of 0.1011. find the substance's half-life in days. round answer to nearest tenth.

 Formula for exponential decay is: 

N = No * e^-kt 

N = 1/2(45) = 22.5 

No = 45 

k = 0.1109 
The solution to your problem is as follows:

Let's try to solve the half-life if it is 45 grams, after which, you will now have an idea on how to solve the problem.

22.5 = 45 * e^(-0.1109t) 

1/2 = e^(-0.1109t) 

ln(1/2) = -0.1109t 

t = (ln(1/2))/(-0.1109) = 6.25 days

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It would be 18 cm