URGENT
Work out the image attached
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Step-by-step explanation:

The first attachment shows the sort of geometry involved. The line of sight from the top of the lighthouse makes a tangent with the earth's surface at the horizon (neglecting optical effects due to the atmosphere).

The hypotenuse of the relevant triangle is (r+h), and the angle is adjacent to the radius, r. Then the cosine relation applies:

  Cos = Adjacent/Hypotenuse

  cos(α) = r/(r+h)

We note that the radius is in km, and the length h is given in meters, so we need to do a conversion to put the numbers in this formula. We don't care so much about the angle itself, but we need its value to find the length of the arc along the earth's surface. That is ...

  s = r·α

so, the distance of interest is found from ...

  cos(α) = 6367/(6367 +0.025)

  r·α = 6367·arccos(6367/6367.025) ≈ 17.84 . . . km

The horizon is about 17.8 km from the observer.

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The second problem requires we find the height value that makes the distance 32 km.

  32 = r·α = 6367·arccos(6367/(6367 +h))

Dividing by the earth's radius and taking the cosine, we have ...

  cos(32/6367) = 6367/(6367 +h)

  h = 6367 -6367/cos(32/6367) ≈ 6367.0804 -6367 = 0.0804 . . . km

The cliffs must be about 80.4 meters high for it to be possible to see that distance.

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)