The areas of the squares formed by the side lengths of the triangles are given for each triangle below. Which triangles are right triangles? Select the three correct answers. (Figures are not drawn to scale.) 3 squares form a triangle. The squares have areas 6 inches squared, 10 inches squared, 8 inches squared.

4 squares form a triangle. The squares have areas 9 inches squared, 25 inches squared, 16 inches squared.

5 squares form a triangle. The squares have areas 25 inches squared, 169 inches squared, 144 inches squared.

6 squares form a triangle. The squares have areas 7 inches squared, 25 inches squared, 24 inches squared.

7 squares form a triangle. The squares have areas 64 inches squared, 225 inches squared, 289 inches squared.

8 squares form a triangle. The squares have areas 10 inches squared, 26 inches squared, 24 inches squared.

options B,C, and E are correct

Step-by-step explanation:

Made a 100% on the test

B,C,E

Step-by-step explanation:

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."