Drag each number to the correct location on the table. Classify each number according to its value.
3.2 x 105
1.9 x 101
2.2 x 10
2.4 x 10°
5.9 x 102
6.1 x 10
2.5 x 104
Greater than 2.4 x 104
Between 1.2 x 102
and 2.4 x 104
Less than 1.2 x 102

3.2 x 10^5 goes in greater than 2.4 x 10^4

1.9 x 10^-1 goes in less than 1.2 x 10^2

2.2 x 10 goes in less than 1.2 x 10^2

2.4 x 10^3 goes in between 1.2 x 10^2 and 2.4 x 10^4

5.9 x 10^2 goes in between 1.2 x 10^2 and 2.4 x 10^4

6.1 x 10 goes in less than 1.2 x 10^2

2.5 x 10^4 goes in greater than 2.4 x 10^4

Step-by-step explanation:

First let's find out what 2.4 x 10^4 and 1.2 x 10^2 is.

2.4 x 10^4 = 24000

1.2 x 10^2 = 120

3.2 x 10^5 is obviously greater than 2.4 x 10^4 because the exponent of ten in 3.2 x 10^5 is one more value than the exponent in 2.4 x 10^4. The decimal is also greater.

1.9 x 10^-1 = .19, which is less than 1.2 x 10^2

2.2 x 10 = 22, less than 1.2 x 10^2

2.4 x 10^3 = 2400, in between 1.2 x 10^2 and 2.4 x 10^4

5.9 x 10^2 = 590, in between 1.2 x 10^2 and 2.4 x 10^4

6.1 x 10 = 61, less than 1.2 x 10^2

2.5 x 10^4 we can solve without doing the math, 2.5 is greater than 2.4 meaning the product will be greater, to check I did the math 2.5 x 10^4 = 25000, greater than 2.4 x 10^4

P.S Next time right ^ before the exponents, so we know they are exponents

Answer above is correct just letting yk

Step-by-step explanation:

my guess would be b and d, but i didn’t actually get out the pen and paper. lol

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt