What is the nth term of the following sequence 4 , 11 ,18 ,25 a). 4+7(n-1)

b). 7+4(n-1)

c). 4*7^n-1

d). 7*4^n-1

A.) nth term = 4 + 7 ( n-1 ).

Step-by-step explanation:

first term = 4

common difference = 11 - 4 = 7

now,

nth term = first term + ( n -1 ) × common difference

so, nth term = 4 + 7( n-1 )

the correct answer is 4 + 7(n-1)

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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