How to evaluate higher powers of i

i^0 = 1

i^1 = i

i^2 = -1

i^3 = -i

i^4 = 1

i^5 = i

i^6 = -1

i^7 = -i

i^8 = 1

i^9 = i

Step-by-step explanation:

Anything raised to 0 is 1

Anything raised to 1 is itself

I just always knew i^2 = -1

I put this rest into the calculator honestly

But if you look at the stuff from i^2, you'll notice there's a pattern (-1, -i, 1, i) and it repeats. I bet if you raise i to the 10th, 11th, 12th, and 13th power, it is going to repeat the same pattern. I hope this helps in any way.

geometry: triangles

solvers

lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

25.45584

well what you have to do is divide 84 by 6 so theanswer

step-by-step explanation:

84 divided by 6 = 14

and that lightbulb changing party must be freaking lit!