The slope of the line below is -2. Use the cordinates of the labeled point to find a point-slope equation of the line

We can not see the image, so i will answer this in a general way.

We know that a linear equation can be written as:

y = a*x + b

Where a is the slope, and b is the y-intercept.

In this case, we know that this line has a slope equal to -2, then the line is:

y = -2*x + b

Now, suppose that in the image we can see that this line passes through the point (j, k)

Then we can replace x by j, and y by k in the line equation, to get:

k = -2*j + b

Now we can solve this for b:

b = k + 2*j

Then we can conclude that a line with a slope equal to -2, that passes through the point (j, k) is:

y = -2*x + (k + 2*j)

answer:

it is general formula that is used to write value to its excet position

a11 a12 a13

a21 a22 a23

it is the example of order 2 by 3 matrix in this

a11 means value occur in 1 st row 1st column

a12 means value occurs in 1st row 2nd column

a13 means value occur in 1st row and 3rd column

a21 means value occurs in 2nd row and 1st column

a22 means value occurs in 2nd row and in 2nd column

a23 means value occurs in 2nd row and in 3rd column

a

step-by-step explanation:

the denominator cannot be the same as one of the factors.

8 denominator times 2 denominator = 16

and 7 numerator time 11 = 77

77/16= 77/16 ( they cannot be further simplified)