A lot runs between two parallel streets. The length of the lot on one of the streets is 160-ft. The length of the lot on the other street is 100-ft. The area of the lot is 14,170 square feet. How far apart are the two streets?

Step-by-step explanation:Area = 1/2(b1 + b2)x h

Area = 18,000 ft^2

b1 = 80 ft

b2 = 100 ft

18,000 = 1/2(80 + 100) x h

36,000 = (180)h

h = 36,000/180

h = 200ft.

This is the distance between streets.

Hope this helps :-)Area = 1/2(b1 + b2)x h

Area = 18,000 ft^2

b1 = 80 ft

b2 = 100 ft

18,000 = 1/2(80 + 100) x h

36,000 = (180)h

h = 36,000/180

h = 200ft.

This is the distance between streets.

Hope this helps :-)

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

answer: answer is b.

[m < b = 120º]

step-by-step explanation: