![Solution,\\Area~of~triangle=\frac{1}{2} (base)(height) = \frac{1}{2}(2x+\frac{1}{4}) (x-8)\\~~~~~~~~~~~~~~~~~~~~~~~~ =\frac{1}{2}[2x^2-16x+\frac{1}{4}x-\frac{1}{4}(8)]\\ ~~~~~~~~~~~~~~~~~~~~~~~~ =\frac{1}{2}[2x^2-\frac{63}{4}x - 2]\\~~~~~~~~~~~~~~~~~~~~~~~~=x^2-\frac{63}{8}x-1](/tpl/images/1104/6158/7f5a9.png)
Please help me find the area of the triangle in terms of x!
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