Laura went to a golf shop that has a golf simulator the simulator estimates the distance that each ball she hates would have gone she hit five balls each with her 2,3,4,5,6,7,8 and 9 irons. The distance of her golf shots are given in the table keep this table window open as you work on the task in this activity when Laura graph the data she got the scatterplot Andrew a line of best fit keep the scatterplot window open as you work on the task when her brother graph the data he got a different scatter plot and drew a line of best fit keep the scatterplot window open as you work on the task and activity what scatter plot much is a data and what is wrong with the incorrect scatterplot

its d. the first coordintaes are 10,32

step-by-step explanation:

(d)

step-by-step explanation:

given: the line in the graph passes through points (5,30) and (6,26).

then, the equation of line is:

now, put y=a(n) and x=n,

hence, option d is correct.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.