| 2. On rectangle ABCD below, if A is located at (3, 4) and B is located at (7,6), is the slope

of BC ?

necal ve

rec

-2

Step-by-step explanation:

Given that:

A = (3, 4) ; B = (7, 6)

In triangle ABCD, AB and BC are Perpendicular lines :

Slope AB = Rise / Run = (y2 - y1) / (x2 - x1)

y2 = 6 ; y1 = 4 ; x2 = 7 ; x1 = 3

Slope AB = (6 - 4) / (7 - 3) = 2 / 4 = 1 / 2

To obtain the slope of BC:

RECALL:

product of the slope of 2 Perpendicular lines = - 1

Slope AB * Slope BC = - 1

1 / 2 * slope BC = - 1

Slope BC = - 1 ÷ 1/2

Slope BC = - 1 * 2/1

Slope BC = - 2

HENCE, slope of BC = - 2

stop using this to cheat on home work

step-by-step explanation:

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step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)