Please Help 1) 24 + r ; r = 9

2) 2a + 3 ; a = 10

3) Bc + 12.3 ; b = 9, c = 4

4) p ÷ q ; p = 24, q = 8

5) 4c - 7.8 ; c = 4

6) c - a ; a = 3, c = 17

7) a ÷ 2c ; a = 20, c = 2

8) 3x - 14 ; x = 5

9) 1.5 + y² ; y = 6

10) t/5 + 6 ; t = 45

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

answer:

125 yards

explanation:

75+50=125. that is my answer

y = 3x+4

step-by-step explanation:

to find the slope

slope = (y2-y1)/ (x2-x1)

    = (-8-4)/ (-4-0)

    = -12/-4

  = 3

using the slope intercept form of a line

y= mx+b

we know the slope is 3

we know the y intercept is 4 ( the point where it crosses the y axis or x=0)

y = 3x+4