Mathematics, 09.02.2021 01:00 Andy769

The tolerance limits for a circuit breaker are Amperes. This means that any circuit breaker that breaks at an amperage less than 39.5 breaks at too low a level and any that breaks at an amperage greater than 40.5 breaks at too high a level. If a shipment of circuit breakers possesses break points that are normally distributed with mean 39.3 and standard deviation 0.2, then what percentage of the shipment is defective

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Answer from: tyler9585

84.13% of the shipment is defective

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Normally distributed with mean 39.3 and standard deviation 0.2

This means that $\mu = 39.3, \sigma = 0.2$

What percentage of the shipment is defective

Less than 39.5 or greater than 40.5.

Less than 39.5:

This is the pvalue of Z when X = 39.5. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{39.5 - 39.3}{0.2}$

Z = 1

Z = 1 has a pvalue of 0.8413.

Greater than 40.5:

1 subtracted by the pvalue of Z when X = 40.5. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{40.5 - 39.3}{0.2}$

Z = 6

Z = 6 has a pvalue of 1

1 - 1 = 0

Total:

0.8413 + 0 = 0.8413

84.13% of the shipment is defective

Answer from: Quest

The graph isn’t that clear

Answer from: Quest

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

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