Use the information given to find a convenient dass width. Then list the class boundaries that can be used to create a relative frequency histogram. (Round your class with up to the nearest multiple of 5. Use the minimum value as the smallest class boundary. Enter your class boundaries as a comma separated list.) 8 classes for 75 measurements; minimum value-20; maximum value = 175
class width
class boundaries

a)

Class width = 19.375

b)

Class Boundaries are;

19.5 - 39.5, 39.5 - 59.5, 59.5 - 79.5, 79.5 - 99.5, 99.5 - 119.5, 119.5 - 139.5, 139.5 - 159.5, 159.5 - 179.5.

Step-by-step explanation:

Given the data in the question;

Class width = Range / Number of classes

Range = maximum - minimum = 175 - 20 = 155

Number of classes = 8

so,

Class width = 155 / 8 = 19.375

∴ the class limits will be

20   - 39

40   - 59

60   - 79

80   - 99

100  - 119

120  - 139

140  - 159

160  - 179

Low class boundary = Lower class limit - 0.5

Upper class boundary = upper class limit + 0.5

so

Class Boundaries are;

19.5 - 39.5, 39.5 - 59.5, 59.5 - 79.5, 79.5 - 99.5, 99.5 - 119.5, 119.5 - 139.5, 139.5 - 159.5, 159.5 - 179.5.

connie < felicia < stew

step-by-step explanation:

stew:

we need to find the slope

m = (y2-y1)/ (x2-x1)

    = (2650-795)/(10-3)

    = 1855/7

265 words per minute

connie:

we need to find the slope

m = (y2-y1)/ (x2-x1)

we have two points (0,0) and (4,800)

m = (800-0)/(4-0)

  m = 800/4

    200 words per minute

felicia:

260 words per minute

200< 260 < 265

connie < felicia < stew