Find two numbers such that the sum of the first and three times the second is 5 and the sum of the second and two times the first is 8.

first number= 19/5

second number= 2/5

Step-by-step explanation:

first number= a

second number= b

a+3b=5   equation 1

b+2a=8  equation 2

using equation 2 we have

b=8-2a

using equation 1 we have

a+3(8-2a)=5  

a+24-6a=5

24-5=6a-a

19=5a

a=19/5 = first number

so using b=8-2a

we have

b=8-2(19/5)

b=8-(38/5)

b=2/5 = second number

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6

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