Given a triangle with a =14 a = 41 and b = 34, what is the length of c? round to the nearest tenth

20.6°

Step-by-step explanation:

Given in a triangle

a = 14 ∠A = 41° and ∠B = 34°

Then we have to find the measure of side c

Since sum of all angles of a triangle is 180°

So   ∠A + ∠B + ∠C = 180°

       41° +  34° + ∠C = 180°

        75° + ∠C = 180°

         ∠C = 180 - 75

               = 105°

Now from sine rule,

= 20.61°

≈ 20.6°

here is a big fat

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.