Mr. Hayes has 11 straw bundles to use forr bedding in his horse stalls. What is the greatest number of stalls he can fill if each stall holds exactly 4 bundles

2 stalls

Step-by-step explanation:

Mr. Hayes has 11 straw bundles to use forr bedding in his horse stalls. What is the greatest number of stalls he can fill if each stall holds exactly 4 bundles

1 stall = 4 bundles

4 bundles = 1 stall

11 bundles = x

Cross Multiply

4x = 11

x = 11/4

x = 2 3/4 stalls

The greatest number of stalls he can build is 2 stalls

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts

17   x 256=4352

sorry if this is wrong, i'm new.

step-by-step explanation: