A plane is flying to Metro City. The plane started its journey 1275 miles from Metro City. Write an equation in standard form to represent the situation if the plane travels a hours at 550 mph and b hours at
590 mph.
Which equation is correctly written in standard form to represent this scenario?
0 590a - 550b = 1275
550a +590b = 1275
590a + 550b = 1275
550a - 5906 = 1275

550a + 590b = 1275

Step-by-step explanation:

We use the following relation to solve this question:

In which v is the velocity, d is the distance and t is the speed.

In this question, we find the distance, so we use:

A plane is flying to Metro City. The plane started its journey 1275 miles from Metro City.

This means that .

Write an equation in standard form to represent the situation if the plane travels a hours at 550 mph and b hours at 590 mph.

This means that .

Which equation is correctly written in standard form to represent this scenario?

1275 = 550a + 590b

550a + 590b = 1275

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!