1) A city has a population of 21,517 based on a census taken in 1998. If the population is expected to grow by 11% annually, what will the population
be in the year 2030? *
A None of these
B 606,900
C 492,573
D 517

B. 606,900

Step-by-step explanation:

Hope it helps

B, 606,900

Step-by-step explanation:

First you'll need to calculate the percentage growth after 32(2030 - 1998) years. to do this you'll need to find 1.11^32 or 28.205, 1.11 being the percentage growth per year and 32 being the number of years passed. then 21,517*28.205 = 606,899.8 which can be rounded to 606,900.

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.