2x + 5y = -24
3x - 5y = 14
Solve by elimination
y and x...
Answers: 2
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The width of a rectangle is 20 units. can the perimeter p of the rectangle be 64 units when its length x is 11 units? no, because p = 2x + 2(20) no, because p ≠2x + 2(20) yes, because p ≠2x + 2(20) yes, because p = 2x + 2(20)
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