Using laws of logarithms, write the expression below as a single logarithm.
6 log(25-x^2) - [log(5+x)+log(5-x)]

If logs are subtracting, you can divide the brackets and if they are adding, you can multiply the brackets. Also, if the number comes before the log, it's can be Taken up as a power. so you end up with:

6log(25-x^2) - [log(5+X) + log(5-X)]

= log(25-x^2) - log(25-x^2)

= log (25-x^2/25-x^2)

= log(1)

log