Identify the correct explanation and the similarity statement for the similar triangles. The figure shows triangles I X D and S E A. Sides I D and D X are congruent. Angle I is 80 degrees. Sides S A and A E are congruent. Angle A is 20 degrees.

By the Isosc. Δ Thm., ∠I ≅ ∠X, so by the Def. of ≅, m∠I = m∠D.
This gives m∠D = 80° by Substitution.
Then, by the Δ Sum Thm., m∠X = 20°. Now apply the Isosc. Δ Thm. and the Δ Sum Thm. to ΔSEA to find that m∠S = m∠E = 80°.
Therefore ΔIXD ~ ΔSEA by AA ~.

By the Isosc. Δ Thm., ∠I ≅ ∠X, so by the Def. of ≅, m∠I = m∠X.
This gives m∠X = 20° by Substitution.
Then, by the Δ Subt. Thm., m∠D = 80°.
Now apply the Isosc. Δ Thm. and the Δ Subt. Thm. to ΔSEA to find that m∠S = m∠E = 80°.
Therefore ΔIXD ~ ΔSEA by SSS ~.

By the Isosc. Δ Thm., ∠I ≅ ∠X, so by the Def. of ≅ , m∠I = m∠X.
This gives m∠X = 80° by substitution.
Then, by the Δ Sum Thm., m∠D = 20°.
Now apply the Isosc. Δ Thm. and the Δ Sum Thm. to ΔSEA to find that m∠S = m∠E = 80°.
Therefore ΔIXD ~ ΔSEA by AA ~.

By the Isosc. Δ Thm., ∠I ≅ ∠X, so by the Def. of ≅, m∠I = m∠D.
This gives m∠D = 80° by Substitution.
Then, by the Δ Subt. Thm., m∠X = 20°.
Now apply the Isosc. Δ Thm. and the Δ Subt. Thm. to ΔSEA to find that m∠S = m∠E = 80°.
Therefore ΔIXD ~ ΔSEA by SSS ~.