Please find the slope of (-2, 4) and (3, -5)

The slope of the line = m = -9/5

Step-by-step explanation:

Given the points

Determining the slope between (-2, 4) and (3, -5)

(x₁, y₁) = (-2, 4)

(x₂, y₂) = (3, -5)

Using the formula

Slope = m =  [y₂ - y₁] /  [x₂ - x₁]  

                 =  [-5 - 4] / [3 - (-2)]

                 = [-9] / [3 + 2]

                 = -9/5

Thus, the slope of the line = m = -9/5  

m = -9/5

Step-by-step explanation:

Taking (-2,4) as (x1,y1), and

Taking (3,-5) as (x2,y2)

Using the slope (m) formula:

= (-5-4)/(3-(-2))

= -9/(3+2)

= -9/5

Hence, the slope is -9/5

Hope this helps and be sure to have a wonderful time ahead at ! :D

a

step-by-step explanation:

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.