Question 9 of 10
What are the zeros of f(x) = x2 + x - 12?

the zeros are f(x= 3) and f(x= -4)

Step-by-step explanation:

x²+x-12

x²+4x-3x-12

x(x+4) -3(x+4)

(x-3) (x+4)

x=3 and x= -4

f(x)= x²+x-12

using x=3;

f(3)= 3²+3-12 = 9+3-12= 12-12=0

using x= -4;

f(-4)= (-4)² + (-4) - 12= 16-4-12= 12-12= 0

the zeros are f(x= 3) and f(x= -4)

sina-sinb

cosb+cosa

tana-tanb

cos0+cos x pi/3

20tan

step-by-step explanation:

i don't know

step-by-step explanation: