This is (compound) probability: Picking two numbers from 1-10 and getting a multiple of 3 both times.

There are 10 counters in the bag and you want the 4

As their is only one for the probability is

1/10

There are now 9 counters left in the bag.

You only want the even ones , which are 2 6 8 and 10 ( four has been taken out)

There are only four even counters in the bag of nine counters so the probability is

4/9

As you want both of these to occur, you need to multiply them

1/10 x 4/9 = 49/90

Step-by-step explanation:

[2, 2.5)

(2.5, 3]

step-by-step explanation:

i think its these two not sure [2, 2.5)

(2.5, 3]