The mean weight of a group of dogs in a dog show is 38 pounds. If a certain dog in the show has a z-score of 0, how much does it weigh?

The weight of dogs x = 38pounds

Step-by-step explanation:

Step(i):-

Given that the mean weight of a group of dogs

       μ = 38 pounds

Let 'x' be the weight of dogs

Let 'x' be the random variable in normal distribution

Given that z-score is zero

Step(ii):-

we know that the z-score

            ⇒  

            ⇒ 0 = x-38

           ⇒  x-38 = 0

          ⇒   x =38

Final -

The weight of dogs x = 38pounds

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?