A bag is filled with green and blue marbles. There are 43 marbles in the bag. If there are 7 more green marbles than blue marbles, find the number of green marbles and the number of blue marbles in the bag.
Equation (use x as your variable):
The number of blue marbles is:
The number of green marbles is:

Blue marbles: 18

Green marbles: 25

Step-by-step explanation:

First off, we have to define our variables.

g = # of green marbles

b = # of blue marbles

We know two equations:

g + b = 43 and g = b + 7

If you're wondering how I got the first equation, it was because the number of green and blue marbles is 43. For the second equation, we know that there are 7 more green marbles than blue marbles.

Now, we have an equation for the number of green marbles. We can plug that equation into the equation g + b = 43.

So, (b + 7) + b = 43.

When we simplify it, we get 2b + 7 = 43.

We subtract 7 from both sides, which gets us 2b = 36.

Now, b = 36/2.

b = 18.

So, we found out the number of blue marbles that we have. We know that g + b = 43. Now, all we have to do is plug in the number of blue marbles into that equation to find out the number of green marbles.

g + 18 = 43.

g = 43 - 18.

g = 25.

Thus, the number of green marbles we have is 25 and the number of blue marbles is 18.

arithmetic sequence: a sequnce in which the diffrence between any two consecutive terms is the same

step-by-step explanation:

the answer is y < -3 or   y > 3

-3y > 7 + 2

-3 y > 9

y < -3