Can you please put steps swell

Step-by-step explanation:

If the vector CD is a multiple of the vector BC

(CD = kBC, where k is a real constant

and k =/= 0),

Then BCD is a straight line.

Vector BC = Vector BA - Vector CA

= (5a - 2b) - (3a + b) = (2a - 3b).

Vector CD = Vector CA + Vector AD

= (3a + b) + (3a - 10b) = (6a - 9b)

Since 3(2a - 3b) = (6a - 9b), => k = 3,

The points B, C and D are collinear.

Hence we conclude BCD is a straight line.

add an image !

step-by-step explanation:

answer is d-29

step-by-step explanation:

since you didn't include the picture, i can give you the description so you know how to pick the correct answer. the third quartile of a data is always shown in a box plot. in the middle of your graph should be a box. the third quartile is the value that goes with the far right edge of the box.