12 What is the equation of the line that is parallel to the
given line and passes through the point (12,-2)?
10
8-
(126)
2
O y=-x + 10
O y=-x + 12
O y=-x-10
O y = x - 12
-to to # 22
8 10 12 14 x
(12.-2)
(0.4)
-8
10
12

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

54.864 meters

step-by-step explanation:

explanation:

step-by-step explanation: