Michel uses the scale drawing and the scale factor to enlarge a square that has a side length of 12 in. A square with side lengths of 12 inches. Scale factor: 3 inches = 2 meters.
Which proportion could Michel use to solve the side length, x, of the enlarged square?
StartFraction 3 inches over 2 meters EndFraction = StartFraction x meters over 12 inches EndFraction
StartFraction x inches over 2 meters EndFraction = StartFraction 3 inches over 12 meters EndFraction
StartFraction 3 inches over x meters EndFraction = StartFraction 2 meters over 12 inches EndFraction
StartFraction 3 inches over 2 meters EndFraction = StartFraction 12 inches over x meters EndFraction

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse

48 / 6 = x

in this case, x will equal the amount of money in each card!

x therefore will be 8.

trent had $8 in each birthday card.