A family has two children. Find the probability that both children are girls, given that at least one of the two is a girl who was born in winter. Please assume that (i) gender is binary, i. e., a boy or a girl, (ii) P (a boy) = P (a girl) = 1/2, (iii) genders of the two children are independent, i. e., knowing one’s gender gives no information about the other’s gender, (iv) four seasons are equally likely, and (v) gender is independent of season.

13

step-by-step explanation:

divide the cost of the total of sodas you bought by the cost of one soda, for example:

$24.57 divided by $1.89 is 13 which means you bought 13 sodas

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

a orange at the grocery store idk what other product that could be

i think the answer is 90 hope this