Find the orthocenter of a triangle with vertices (−8, 11), (−3, 11), and (−3, −12). The orthocenter of triangle is at ( , ).

( -3, 11)

Step-by-step explanation:

find the equation of the line between points ( -8, 11) and (-3, 11)

y= mx +b , where m is slope snd b is y-intercept

m = (y2-y1)/ (x2-x1) = 11-11/ -8- -3 = 0/ -5 = 0 ( if slope is o is a horizontal line)

y = 0x + b and pick a point to find b

11 = 0*-8 + b so b= 11

y = 11 is the equation of the line between points ( -8, 11) and (-3, 11) and the equation of its perpendicular line is x=-3

the equation of the line between points  (-3, 11) and ( -3, -12) is x= -3 and the perpendicular to it is y= 11

so we have a right triangle so the ortho center is at (-3, 11) where the vertex of the 90 degree angle is

idk

step-by-step explanation:

payback

2

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