2x + 3y = 16
2 + 2y = 10

1. −

2

x

+

3

y

=

16

Solve for

y

.

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Add

2

x

to both sides of the equation.

3

y

=

16

+

2

x

Divide each term by

3

and simplify.

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y

=

16

3

+

2

x

3

Rewrite in slope-intercept form.

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The slope-intercept form is

y

=

m

x

+

b

, where

m

is the slope and

b

is the y-intercept.

y

=

m

x

+

b

Reorder

16

3

and

2

x

3

.

y

=

2

x

3

+

16

3

Rewrite in slope-intercept form.

y

=

2

3

x

+

16

3

Use the slope-intercept form to find the slope and y-intercept.

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Find the values of

m

and

b

using the form

y

=

m

x

+

b

.

m

=

2

3

b

=

16

3

The slope of the line is the value of

m

, and the y-intercept is the value of

b

.

Slope:

2

3

y-intercept:

16

3

Any line can be graphed using two points. Select two

x

values, and plug them into the equation to find the corresponding

y

values.

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Choose

1

to substitute in for

x

to find the ordered pair.

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y

=

6

Choose

0

to substitute in for

x

to find the ordered pair.

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y

=

16

3

Create a table of the

x

and

y

values.

x

y

0

16

3

1

6

Graph the line using the slope and the y-intercept, or the points.

Slope:

2

3

y-intercept:

16

3

x

y

0

16

3

1

6

2.

Isolate the variable by dividing each side by factors that don't contain the variable.

y=4

i dont understand the question? ?

step-by-step explanation:

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)