Find the measure of angle C and angle D. show your work.

C=40 degrees D=76 degrees

Step-by-step explanation:

Because of a theorem angle c and d equal angle DEF

so here is our equation:4y+(7y+6)=116

Open the parentheses

4y+7y+6=116

-6 on both sides

4y+7y=110

11y=110

Divide both sides by 11

y=10

Now we have to substitute

C=4y=4(10)=40

D=7y+6=7(10)+6=70+6=76

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.