When using the inspection method, the number you would add to (and subtract from) the constant term of the numerator so the polynomial in the numerator will have (x+ 3) as a factor is

Question:

Consider the expression

When using the inspection method the number you would add to (and subtract from) the constant term of the numerator so the polynomial in the numerator will have (x + 3) as a factor is?

The constant to add is 4

Step-by-step explanation:

Given

First, we need to get an expression that has x + 3 has its factor.

Represent this expression with:

Expand

Group like terms

Compare the above expression to:

However, we only consider solving for k

Subtract 3 from both sides

Substitute -2 for k in

So, the expression that has a factor of x + 3 is

To get the constant term to add/subtract, we have:

Open brackets

Collect Like Terms

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step-by-step explanation: