5. There are 29 students available to represent the upperclassmen at a fair. 13 are juniors and 16 are seniors. What is the probability, as a percent that
a senior and junior will be chosen?

senior and junior? that would be a perfect 100%, 29/29

Step-by-step explanation:

Unless I'm incorrect, this question states the probability of BOTH a senior AND junior being chosen, which would be 100% or again, 29/29

The probability that a senior will be chosen is 55.2% or 16/29. And The probability a Junior will be chosen is 44.8% or 13/29.

Explanation:

Since the total students are 29. I put the 29 as the denominator and converted these fractions into percentages to find my answer.

in simplified version   it would be x ≤-4

step-by-step explanation:

multiply each term in x ≤-4 by -1

answer: a. 13/44

step-by-step explanation: judging by the information given to us, we are looking for experimental probability. we can see that 13 males have chosen chocolate ice cream. there are 44 ice creams in total (remember that the total is always the denominator). so our answer is 13/44.