Please answer ASAP Find the equation of the parabola with its focus at (6,2) and its directrix y = 0.

A)

y = 1∕4(x – 1)^ 2 + 6

B)

y = 4(x – 6)^ 2 + 1

C)

y = 1∕4(x – 6)^ 2 + 1

D)

y = –1∕4(x – 6)^ 2 + 1

i need a picture

step-by-step explanation:

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

1) 2/5

2) zero=0/1

3) zero=0/2

4) -4/5

5) undefined=3/0

17

step-by-step explanation:

51/3=17

thus 17 is your answer.