WILL MARK BRAINLIEST! THANK YOU An equilateral triangle has a side length of 40.

Another side of the same triangle measures 3x + y.
The third side of the same triangle measures 4x - 2y.
What are the values of x and y that would keep the triangle equilateral?

x=12, y=4

Step-by-step explanation:

All the sides are the same length.

3x+y = 40

4x-2y = 40

Eliminate y terms: divide second equation by 2 and add to first equation

2x-y = 20

3x+y = 40

5x = 60

x = 12

y = 40-3x = 4

We know that all sides of the equilateral triangle is equal.

Given :---

An equilateral triangle has a side length of 40.

Another side of the same triangle measures

3x + y.

The third side of the same triangle measures

4x - 2y.

According to the above problem, the equation are

3x+y=40(i) and 4x-2y=40(ii)

Divide the equation (ii) by 2, we get

2x-y=20(iii)

Now solving for x and y we get,

3x+y=40(i)

2x-y=20(iii)

5x =60

x=60/5

x=12

Putting the value of x in equation in equation (iii) we get

24-y=20

y=24-20

y=4

The values of x and y that would keep the triangle equilateral are 12 and 4 respectively.

plz yuo

step-by-step explanation:

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

eventually after a few more steps, your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x