Eliminate the parameter t. Find a rectangular equation for the plane curve defined by the parametric equations. * Brainliest for answers and explanations * PLEASE PLEASE PLEASEE HELP

• (1) x= sqrt t, y=4t+3; 0 ≤ t ≤ 4

A) y = - 3x ^ 2 + 19; 0 ≤ x ≤ 2
B ) y = - 3x + 19; 0 ≤ x ≤ 2
C) y=4x^ 2 +3; 0 ≤ x ≤ 2
D ) y=3x^ 2 +4; -1 ≤ x ≤ 2

• (2) x=2t, y=t+2; -2 ≤ t ≤ 3

A ) y=x ^2 + 1; - 2 ≤ x ≤ 2
B) y= 1/2x -2; -∞ C) y= 1/2x +2; -4 ≤ x ≤ 6
D ) y=-2x+2; -∞

1. C

2. C

Step-by-step explanation:

1. x = , y = 4t +3

Solve for t:

t =

Plug in t:

y = 4( ) +3

y = 4 +3

2. x = 2t, y = t + 2

Solve for t:

t = x/2

Plug in t:

y = 1/2x + 2

1)is not similar since corresponding sides are not in the same ratio

2)are similar since corresponding sides are in the same ratio and corresponding angles are equal

hope it will

#faazmessi

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841