Solve the inequality x^2+ 3x-4 ≥ 0

Finding the roots of the given equation as shown below:

x

2

+3x−4>0

x

2

+4x−x−4>0

x(x+4)−1(x+4)>0

(x+4)(x−1)>0

Case-1:- Case-2:-

x−1>0 and x+4>0 x−1<0 and x+4<0

x>1 and x>−4 x<1 and x<−4

from above two we get from above two we get

x>1 …(1) x<−4 …(2)

From (1) and (2)

x lies between (−∞,−4)∪(1,+∞).

i do not know this sorry : (

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)