Find the sum of all positive integers less than 200 which are divisible by 3

we will use the sum of natural number series formula

if S=1+2+3+4+n, then

S= n(n+1) ;

2

Now, sum of all +ve integers from 0 to 200 is given by

S=0+1+2+3+200

=> S=200(200+1)/2;

=>S=20100;

Sum of all +ve integers divisible by 5 is given by

R=0+5+10+15+20+25+30+200

R=5(1+2+3+4+5+6+40)

R=5*40(40+1)/2

R=4100 ;

therefore the sum of all +ve integers <200 and not divisible by 5=S-R=16000

Step-by-step explanation:

answer: 2x + 2 − 2 = 10 − 2; subtraction property of equality

step-by-step explanation:

whole number data type

step-by-step explanation:

as whole number type represents whole number

like 1, 2 ,3, 4

in other words the whole numbers are those numbers which cannot be written infraction.

since we can take days as a whole number i.e 1 day 2 day and we cannot write 1.2 day hence we will use whole number data type